Integrand size = 11, antiderivative size = 43 \[ \int x^4 (a+b x)^3 \, dx=\frac {a^3 x^5}{5}+\frac {1}{2} a^2 b x^6+\frac {3}{7} a b^2 x^7+\frac {b^3 x^8}{8} \]
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Time = 0.01 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {45} \[ \int x^4 (a+b x)^3 \, dx=\frac {a^3 x^5}{5}+\frac {1}{2} a^2 b x^6+\frac {3}{7} a b^2 x^7+\frac {b^3 x^8}{8} \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (a^3 x^4+3 a^2 b x^5+3 a b^2 x^6+b^3 x^7\right ) \, dx \\ & = \frac {a^3 x^5}{5}+\frac {1}{2} a^2 b x^6+\frac {3}{7} a b^2 x^7+\frac {b^3 x^8}{8} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.00 \[ \int x^4 (a+b x)^3 \, dx=\frac {a^3 x^5}{5}+\frac {1}{2} a^2 b x^6+\frac {3}{7} a b^2 x^7+\frac {b^3 x^8}{8} \]
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Time = 0.16 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.84
method | result | size |
gosper | \(\frac {1}{5} a^{3} x^{5}+\frac {1}{2} a^{2} b \,x^{6}+\frac {3}{7} a \,b^{2} x^{7}+\frac {1}{8} b^{3} x^{8}\) | \(36\) |
default | \(\frac {1}{5} a^{3} x^{5}+\frac {1}{2} a^{2} b \,x^{6}+\frac {3}{7} a \,b^{2} x^{7}+\frac {1}{8} b^{3} x^{8}\) | \(36\) |
norman | \(\frac {1}{5} a^{3} x^{5}+\frac {1}{2} a^{2} b \,x^{6}+\frac {3}{7} a \,b^{2} x^{7}+\frac {1}{8} b^{3} x^{8}\) | \(36\) |
risch | \(\frac {1}{5} a^{3} x^{5}+\frac {1}{2} a^{2} b \,x^{6}+\frac {3}{7} a \,b^{2} x^{7}+\frac {1}{8} b^{3} x^{8}\) | \(36\) |
parallelrisch | \(\frac {1}{5} a^{3} x^{5}+\frac {1}{2} a^{2} b \,x^{6}+\frac {3}{7} a \,b^{2} x^{7}+\frac {1}{8} b^{3} x^{8}\) | \(36\) |
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none
Time = 0.21 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.81 \[ \int x^4 (a+b x)^3 \, dx=\frac {1}{8} \, b^{3} x^{8} + \frac {3}{7} \, a b^{2} x^{7} + \frac {1}{2} \, a^{2} b x^{6} + \frac {1}{5} \, a^{3} x^{5} \]
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Time = 0.02 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.86 \[ \int x^4 (a+b x)^3 \, dx=\frac {a^{3} x^{5}}{5} + \frac {a^{2} b x^{6}}{2} + \frac {3 a b^{2} x^{7}}{7} + \frac {b^{3} x^{8}}{8} \]
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none
Time = 0.22 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.81 \[ \int x^4 (a+b x)^3 \, dx=\frac {1}{8} \, b^{3} x^{8} + \frac {3}{7} \, a b^{2} x^{7} + \frac {1}{2} \, a^{2} b x^{6} + \frac {1}{5} \, a^{3} x^{5} \]
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none
Time = 0.31 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.81 \[ \int x^4 (a+b x)^3 \, dx=\frac {1}{8} \, b^{3} x^{8} + \frac {3}{7} \, a b^{2} x^{7} + \frac {1}{2} \, a^{2} b x^{6} + \frac {1}{5} \, a^{3} x^{5} \]
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Time = 0.03 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.81 \[ \int x^4 (a+b x)^3 \, dx=\frac {a^3\,x^5}{5}+\frac {a^2\,b\,x^6}{2}+\frac {3\,a\,b^2\,x^7}{7}+\frac {b^3\,x^8}{8} \]
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